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Exercise 10.1|Class seven| Congruence| Part – 2

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Problem – 5: In the figure, AD = AE, BD = CE and ∠AEC = ∠ADB. Prove that AB = AC. Particular enunciation: In the figure, AD = AE, BD = CE and ∠AEC = ∠ADB. We have to prove that AB = AC. Proof: In ∆ACE and ∆ADB, AD = AE [Given] BD = ...

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